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Partial Fraction Decomposition Calculator

Partial Fraction Decomposition Calculator
Break down complex rational expressions into simpler fractions

Enter a polynomial like 3x + 5 or x^2 - 2

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What is Partial Fraction Decomposition?

Partial fraction decomposition is a technique used to break down complex rational expressions (fractions with polynomials) into simpler fractions. This process is particularly useful in calculus for integrating rational functions and in solving differential equations.

When to Use Partial Fraction Decomposition

Partial fraction decomposition is typically used when:

  • You need to integrate a complex rational function
  • You're working with rational expressions in differential equations
  • You want to simplify complex fractions for easier manipulation
  • You're finding inverse Laplace transforms in engineering and physics

How Partial Fraction Decomposition Works

The process involves several key steps:

  1. Ensure the numerator's degree is less than the denominator's (perform long division if needed)
  2. Factor the denominator completely
  3. Write out the partial fraction decomposition form based on the factors
  4. Solve for the unknown coefficients using various methods (equating coefficients, substituting values, etc.)

Types of Factors and Their Decomposition

Linear Factors: (ax + b)

For each linear factor (ax + b) that appears n times in the denominator, the decomposition includes terms of the form:

A₁/(ax + b) + A₂/(ax + b)² + ... + Aₙ/(ax + b)ⁿ

Quadratic Factors: (ax² + bx + c)

For irreducible quadratic factors (ax² + bx + c) that appear n times, the decomposition includes:

(A₁x + B₁)/(ax² + bx + c) + (A₂x + B₂)/(ax² + bx + c)² + ... + (Aₙx + Bₙ)/(ax² + bx + c)ⁿ

Example of Partial Fraction Decomposition

Example: Decompose (3x + 5)/((x + 1)(x - 2))

Step 1: Write the partial fraction form

(3x + 5)/((x + 1)(x - 2)) = A/(x + 1) + B/(x - 2)

Step 2: Multiply both sides by (x + 1)(x - 2)

3x + 5 = A(x - 2) + B(x + 1)

Step 3: Find the coefficients by substituting values

When x = -1: 3(-1) + 5 = A(-1 - 2) + B(0) = -3A

Therefore: 2 = -3A, so A = -2/3

When x = 2: 3(2) + 5 = A(0) + B(2 + 1) = 3B

Therefore: 11 = 3B, so B = 11/3

Step 4: Write the final decomposition

(3x + 5)/((x + 1)(x - 2)) = -2/3/(x + 1) + 11/3/(x - 2)